Optimal. Leaf size=79 \[ \frac{5 x}{16 a^3 \left (a+b x^2\right )}+\frac{5 x}{24 a^2 \left (a+b x^2\right )^2}+\frac{5 \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )}{16 a^{7/2} \sqrt{b}}+\frac{x}{6 a \left (a+b x^2\right )^3} \]
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Rubi [A] time = 0.036823, antiderivative size = 79, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 3, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.15, Rules used = {28, 199, 205} \[ \frac{5 x}{16 a^3 \left (a+b x^2\right )}+\frac{5 x}{24 a^2 \left (a+b x^2\right )^2}+\frac{5 \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )}{16 a^{7/2} \sqrt{b}}+\frac{x}{6 a \left (a+b x^2\right )^3} \]
Antiderivative was successfully verified.
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Rule 28
Rule 199
Rule 205
Rubi steps
\begin{align*} \int \frac{1}{\left (a^2+2 a b x^2+b^2 x^4\right )^2} \, dx &=b^4 \int \frac{1}{\left (a b+b^2 x^2\right )^4} \, dx\\ &=\frac{x}{6 a \left (a+b x^2\right )^3}+\frac{\left (5 b^3\right ) \int \frac{1}{\left (a b+b^2 x^2\right )^3} \, dx}{6 a}\\ &=\frac{x}{6 a \left (a+b x^2\right )^3}+\frac{5 x}{24 a^2 \left (a+b x^2\right )^2}+\frac{\left (5 b^2\right ) \int \frac{1}{\left (a b+b^2 x^2\right )^2} \, dx}{8 a^2}\\ &=\frac{x}{6 a \left (a+b x^2\right )^3}+\frac{5 x}{24 a^2 \left (a+b x^2\right )^2}+\frac{5 x}{16 a^3 \left (a+b x^2\right )}+\frac{(5 b) \int \frac{1}{a b+b^2 x^2} \, dx}{16 a^3}\\ &=\frac{x}{6 a \left (a+b x^2\right )^3}+\frac{5 x}{24 a^2 \left (a+b x^2\right )^2}+\frac{5 x}{16 a^3 \left (a+b x^2\right )}+\frac{5 \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )}{16 a^{7/2} \sqrt{b}}\\ \end{align*}
Mathematica [A] time = 0.0344089, size = 66, normalized size = 0.84 \[ \frac{33 a^2 x+40 a b x^3+15 b^2 x^5}{48 a^3 \left (a+b x^2\right )^3}+\frac{5 \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )}{16 a^{7/2} \sqrt{b}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.045, size = 66, normalized size = 0.8 \begin{align*}{\frac{x}{6\,a \left ( b{x}^{2}+a \right ) ^{3}}}+{\frac{5\,x}{24\,{a}^{2} \left ( b{x}^{2}+a \right ) ^{2}}}+{\frac{5\,x}{16\,{a}^{3} \left ( b{x}^{2}+a \right ) }}+{\frac{5}{16\,{a}^{3}}\arctan \left ({bx{\frac{1}{\sqrt{ab}}}} \right ){\frac{1}{\sqrt{ab}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.78971, size = 541, normalized size = 6.85 \begin{align*} \left [\frac{30 \, a b^{3} x^{5} + 80 \, a^{2} b^{2} x^{3} + 66 \, a^{3} b x - 15 \,{\left (b^{3} x^{6} + 3 \, a b^{2} x^{4} + 3 \, a^{2} b x^{2} + a^{3}\right )} \sqrt{-a b} \log \left (\frac{b x^{2} - 2 \, \sqrt{-a b} x - a}{b x^{2} + a}\right )}{96 \,{\left (a^{4} b^{4} x^{6} + 3 \, a^{5} b^{3} x^{4} + 3 \, a^{6} b^{2} x^{2} + a^{7} b\right )}}, \frac{15 \, a b^{3} x^{5} + 40 \, a^{2} b^{2} x^{3} + 33 \, a^{3} b x + 15 \,{\left (b^{3} x^{6} + 3 \, a b^{2} x^{4} + 3 \, a^{2} b x^{2} + a^{3}\right )} \sqrt{a b} \arctan \left (\frac{\sqrt{a b} x}{a}\right )}{48 \,{\left (a^{4} b^{4} x^{6} + 3 \, a^{5} b^{3} x^{4} + 3 \, a^{6} b^{2} x^{2} + a^{7} b\right )}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 0.62227, size = 129, normalized size = 1.63 \begin{align*} - \frac{5 \sqrt{- \frac{1}{a^{7} b}} \log{\left (- a^{4} \sqrt{- \frac{1}{a^{7} b}} + x \right )}}{32} + \frac{5 \sqrt{- \frac{1}{a^{7} b}} \log{\left (a^{4} \sqrt{- \frac{1}{a^{7} b}} + x \right )}}{32} + \frac{33 a^{2} x + 40 a b x^{3} + 15 b^{2} x^{5}}{48 a^{6} + 144 a^{5} b x^{2} + 144 a^{4} b^{2} x^{4} + 48 a^{3} b^{3} x^{6}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.15096, size = 76, normalized size = 0.96 \begin{align*} \frac{5 \, \arctan \left (\frac{b x}{\sqrt{a b}}\right )}{16 \, \sqrt{a b} a^{3}} + \frac{15 \, b^{2} x^{5} + 40 \, a b x^{3} + 33 \, a^{2} x}{48 \,{\left (b x^{2} + a\right )}^{3} a^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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